HackerRank•May 23, 2025
Arrays - DS
Hazrat Ali
HackerRank
An array is a data structure that stores elements of the same type in a contiguous block of memory. In an array, , of size , each memory location has some unique index, (where ), that can be referenced as or .
Your task is to reverse an array of integers.
Note: If you've already solved our C++ domain's Arrays Introduction challenge, you may want to skip this.
Example
Return .
Function Description
Complete the function with the following parameter(s):
- : the array to reverse
Returns
- : the reversed array
Input Format
The first line contains an integer, , the number of integers in .
The second line contains space-separated integers that make up .
Sample Input 1
4
1 4 3 2
1 4 3 2
Sample Output 1
2 3 4 1
Solution
#include <bits/stdc++.h>
using namespace std;
string ltrim(const string &);
string rtrim(const string &);
vector<string> split(const string &);
/*
* Complete the 'reverseArray' function below.
*
* The function is expected to return an INTEGER_ARRAY.
* The function accepts INTEGER_ARRAY a as parameter.
*/
vector<int>& reverseArray(vector<int>& a) {
int middle = a.size() / 2;
for (int i = 0; i < middle; i++)
swap(a[i], a[a.size() - i - 1]);
return a;
}
int main()
{
ofstream fout(getenv("OUTPUT_PATH"));
string arr_count_temp;
getline(cin, arr_count_temp);
int arr_count = stoi(ltrim(rtrim(arr_count_temp)));
string arr_temp_temp;
getline(cin, arr_temp_temp);
vector<string> arr_temp = split(rtrim(arr_temp_temp));
vector<int> arr(arr_count);
for (int i = 0; i < arr_count; i++) {
int arr_item = stoi(arr_temp[i]);
arr[i] = arr_item;
}
vector<int> res = reverseArray(arr);
for (size_t i = 0; i < res.size(); i++) {
fout << res[i];
if (i != res.size() - 1) {
fout << " ";
}
}
fout << "\n";
fout.close();
return 0;
}
string ltrim(const string &str) {
string s(str);
s.erase(
s.begin(),
find_if(s.begin(), s.end(), not1(ptr_fun<int, int>(isspace)))
);
return s;
}
string rtrim(const string &str) {
string s(str);
s.erase(
find_if(s.rbegin(), s.rend(), not1(ptr_fun<int, int>(isspace))).base(),
s.end()
);
return s;
}
vector<string> split(const string &str) {
vector<string> tokens;
string::size_type start = 0;
string::size_type end = 0;
while ((end = str.find(" ", start)) != string::npos) {
tokens.push_back(str.substr(start, end - start));
start = end + 1;
}
tokens.push_back(str.substr(start));
return tokens;
}