HackerRank•Mar 29, 2025
Migratory Birds
Hazrat Ali
HackerRank
Given an array of bird sightings where every element represents a bird type id, determine the id of the most frequently sighted type. If more than 1 type has been spotted that maximum amount, return the smallest of their ids.
Example
There are two each of types and , and one sighting of type . Pick the lower of the two types seen twice: type .
Function Description
Complete the migratoryBirds function in the editor below.
migratoryBirds has the following parameter(s):
- int arr[n]: the types of birds sighted
Returns
- int: the lowest type id of the most frequently sighted birds
Input Format
The first line contains an integer, , the size of .
The second line describes as space-separated integers, each a type number of the bird sighted.
Constraints
- It is guaranteed that each type is , , , , or .
Sample Input 0
6 1 4 4 4 5 3
Sample Output 0
4
Solution :
#!/bin/python3
import math
import os
import random
import re
import sys
#
# Complete the 'migratoryBirds' function below.
#
# The function is expected to return an INTEGER.
# The function accepts INTEGER_ARRAY arr as parameter.
#
def migratoryBirds(arr):
bird_freq = [0, 0, 0, 0, 0, 0]
for i in range(len(arr)):
bird_freq[arr[i]] += 1
return bird_freq.index(max(bird_freq))
if __name__ == '__main__':
fptr = open(os.environ['OUTPUT_PATH'], 'w')
arr_count = int(input().strip())
arr = list(map(int, input().rstrip().split()))
result = migratoryBirds(arr)
fptr.write(str(result) + '\n')
fptr.close()