HackerRank•May 12, 2025
Lonely Integer
Hazrat Ali
HackerRank
Given an array of integers, where all elements but one occur twice, find the unique element.
Example
The unique element is .
Function Description
Complete the lonelyinteger function in the editor below.
lonelyinteger has the following parameter(s):
- int a[n]: an array of integers
Returns
- int: the element that occurs only once
Input Format
The first line contains a single integer, , the number of integers in the array.
The second line contains space-separated integers that describe the values in .
Constraints
- It is guaranteed that is an odd number and that there is one unique element.
- , where .
Sample Input 0
1
1
Sample Output 0
1
Explanation 0
There is only one element in the array, thus it is unique.
Sample Input 1
3
1 1 2
Sample Output 1
2
Explanation 1
We have two 's, and is unique.
Sample Input 2
5
0 0 1 2 1
Sample Output 2
2
Solution
#include <bits/stdc++.h>
using namespace std;
string ltrim(const string &);
string rtrim(const string &);
vector<string> split(const string &);
/*
* Complete the 'lonelyinteger' function below.
*
* The function is expected to return an INTEGER.
* The function accepts INTEGER_ARRAY a as parameter.
*/
int lonelyinteger(vector<int>& a) {
sort(a.begin(), a.end());
int i = 0;
while ((i <= a.size() - 1) && !(a[i] ^ a[i + 1])) {
i += 2;
}
cout << a[i] << endl;
return a[i];
}
int main()
{
ofstream fout(getenv("OUTPUT_PATH"));
string n_temp;
getline(cin, n_temp);
int n = stoi(ltrim(rtrim(n_temp)));
string a_temp_temp;
getline(cin, a_temp_temp);
vector<string> a_temp = split(rtrim(a_temp_temp));
vector<int> a(n);
for (int i = 0; i < n; i++) {
int a_item = stoi(a_temp[i]);
a[i] = a_item;
}
int result = lonelyinteger(a);
fout << result << "\n";
fout.close();
return 0;
}
string ltrim(const string &str) {
string s(str);
s.erase(
s.begin(),
find_if(s.begin(), s.end(), not1(ptr_fun<int, int>(isspace)))
);
return s;
}
string rtrim(const string &str) {
string s(str);
s.erase(
find_if(s.rbegin(), s.rend(), not1(ptr_fun<int, int>(isspace))).base(),
s.end()
);
return s;
}
vector<string> split(const string &str) {
vector<string> tokens;
string::size_type start = 0;
string::size_type end = 0;
while ((end = str.find(" ", start)) != string::npos) {
tokens.push_back(str.substr(start, end - start));
start = end + 1;
}
tokens.push_back(str.substr(start));
return tokens;
}