Leetcode•Mar 22, 2025
526. Beautiful Arrangement
Hazrat Ali
Leetcode
Suppose you have n
integers labeled 1
through n
. A permutation of those n
integers perm
(1-indexed) is considered a beautiful arrangement if for every i
(1 <= i <= n
), either of the following is true:
perm[i]
is divisible byi
.i
is divisible byperm[i]
.
Given an integer n
, return the number of the beautiful arrangements that you can construct.
Example 1:
Input: n = 2 Output: 2 Explanation: The first beautiful arrangement is [1,2]: - perm[1] = 1 is divisible by i = 1 - perm[2] = 2 is divisible by i = 2 The second beautiful arrangement is [2,1]: - perm[1] = 2 is divisible by i = 1 - i = 2 is divisible by perm[2] = 1
Example 2:
Input: n = 1 Output: 1
Solution
/**
* @param {number} N
* @return {number}
*/
const countArrangement = N => {
const result = [];
backtracking(N, 0, {}, [], result);
return result.length;
};
const backtracking = (N, index, used, solution, result) => {
if (index === N) {
result.push(solution.slice());
return;
}
for (let i = 1; i <= N; i++) {
if (!used[i] && ((index + 1) % i === 0 || i % (index + 1) === 0)) {
used[i] = true;
solution.push(i);
backtracking(N, index + 1, used, solution, result);
used[i] = false;
solution.pop();
}
}
};