HackerRank•Jun 05, 2025
Delete duplicate-value nodes from a sorted linked list
Hazrat Ali
HackerRank
Delete nodes and return a sorted list with each distinct value in the original list. The given head pointer may be null indicating that the list is empty.
Example
refers to the first node in the list .
Remove 1 of the data values and return pointing to the revised list .
Function Description
Complete the removeDuplicates function in the editor below.
removeDuplicates has the following parameter:
- SinglyLinkedListNode pointer head: a reference to the head of the list
Returns
- SinglyLinkedListNode pointer: a reference to the head of the revised list
Input Format
The first line contains an integer , the number of test cases.
The format for each test case is as follows:
The first line contains an integer , the number of elements in the linked list.
Each of the next lines contains an integer, the value for each of the elements of the linked list.
Constraints
Sample Input
STDIN Function
----- --------
1 t = 1
5 n = 5
1 data values = 1, 2, 2, 3, 4
2
2
3
4
Sample Output
1 2 3 4
Solution
#include <bits/stdc++.h>
using namespace std;
class SinglyLinkedListNode {
public:
int data;
SinglyLinkedListNode *next;
SinglyLinkedListNode(int node_data) {
this->data = node_data;
this->next = nullptr;
}
};
class SinglyLinkedList {
public:
SinglyLinkedListNode *head;
SinglyLinkedListNode *tail;
SinglyLinkedList() {
this->head = nullptr;
this->tail = nullptr;
}
void insert_node(int node_data) {
SinglyLinkedListNode* node = new SinglyLinkedListNode(node_data);
if (!this->head) {
this->head = node;
} else {
this->tail->next = node;
}
this->tail = node;
}
};
void print_singly_linked_list(SinglyLinkedListNode* node, string sep, ofstream& fout) {
while (node) {
fout << node->data;
node = node->next;
if (node) {
fout << sep;
}
}
}
void free_singly_linked_list(SinglyLinkedListNode* node) {
while (node) {
SinglyLinkedListNode* temp = node;
node = node->next;
free(temp);
}
}
/*
* Complete the 'removeDuplicates' function below.
*
* The function is expected to return an INTEGER_SINGLY_LINKED_LIST.
* The function accepts INTEGER_SINGLY_LINKED_LIST llist as parameter.
*/
/*
* For your reference:
*
* SinglyLinkedListNode {
* int data;
* SinglyLinkedListNode* next;
* };
*
*/
SinglyLinkedListNode* removeDuplicates(SinglyLinkedListNode* head) {
if (!head) return head;
SinglyLinkedListNode* current = head->next;
SinglyLinkedListNode* previous = head;
while (current != NULL) {
if (current->data == previous->data) {
SinglyLinkedListNode* temp = current;
current = current->next;
previous->next = current;
free(temp);
}
else {
previous = current;
current = current->next;
}
}
return head;
}
int main()
{
ofstream fout(getenv("OUTPUT_PATH"));
int t;
cin >> t;
cin.ignore(numeric_limits<streamsize>::max(), '\n');
for (int t_itr = 0; t_itr < t; t_itr++) {
SinglyLinkedList* llist = new SinglyLinkedList();
int llist_count;
cin >> llist_count;
cin.ignore(numeric_limits<streamsize>::max(), '\n');
for (int i = 0; i < llist_count; i++) {
int llist_item;
cin >> llist_item;
cin.ignore(numeric_limits<streamsize>::max(), '\n');
llist->insert_node(llist_item);
}
SinglyLinkedListNode* llist1 = removeDuplicates(llist->head);
print_singly_linked_list(llist1, " ", fout);
fout << "\n";
free_singly_linked_list(llist1);
}
fout.close();
return 0;
}